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4.9x^2+3.59x-3=0
a = 4.9; b = 3.59; c = -3;
Δ = b2-4ac
Δ = 3.592-4·4.9·(-3)
Δ = 71.6881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.59)-\sqrt{71.6881}}{2*4.9}=\frac{-3.59-\sqrt{71.6881}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.59)+\sqrt{71.6881}}{2*4.9}=\frac{-3.59+\sqrt{71.6881}}{9.8} $
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